CBSE Class 12 · 2020 · Current ElectricityMultiple Choice

Two resistors

R_{1}

and

R_{2}

4 Ω

and

6 Ω

are connected in parallel across a battery. The ratio of power dissipated in them,

P_{1} : P_{2}

, will be:

Answer: (B)

Solution

In parallel both resistors have the same potential difference

V

, so

P = \frac{V ^{2}}{R}

gives

\frac{P _{1}}{P _{2}} = \frac{R _{2}}{R _{1}} = \frac{6}{4} = \frac{3}{2} .

CBSE Class 12 Board · 2020 · Single correct option