CBSE Class 12 · 2010 · All India · Magnetic Properties of MatterShort Answer

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The horizontal component of the earth's magnetic field at a place equals its vertical component there. Find the value of the angle of dip at that place. What is the ratio of the horizontal component to the total magnetic field of the earth at that place?

Answer: $δ = 4 5^{\circ}$ ; $\frac{B _{H}}{B _{E}} = \frac{1}{2}$ .

Solution

Given

B_{H} = B_{V}

, so

tan δ = \frac{B _{V}}{B _{H}} = 1 \Rightarrow δ = 4 5^{\circ} .

The ratio of horizontal component to the total field is

\frac{B _{H}}{B _{E}} = cos δ = cos 4 5^{\circ} = \frac{1}{2} .

δ = 4 5^{\circ}, \frac{B _{H}}{B _{E}} = \frac{1}{2}

CBSE Class 12 Board · 2010 · All India · Subjective

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