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CBSE Class 12 · 2013 · Modern PhysicsVery Short Answer

Write the expression for the de-Broglie wavelength associated with a charged particle having charge

q

and mass

m

, when it is accelerated by a potential

V

.

Answer: $λ = \frac{h}{2 m q V}$

Solution

Kinetic energy gained

= q V = \frac{1}{2} m v^{2}

, so momentum

p = 2 m q V

.

λ = \frac{h}{p} = \frac{h}{2 m q V} .

λ = \frac{h}{2 m q V}

CBSE Class 12 Board · 2013 · Subjective

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