CBSE Class 12 · 2010 · Modern PhysicsShort Answer

A heavy nucleus

X

of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments

Y

and

Z

of mass numbers 110 and 130. The binding energy of nucleons in

Y

and

Z

is 8.5 MeV per nucleon. Calculate the energy

Q

released per fission in MeV.

Answer: $Q = 216 MeV$

Solution

Total binding energies:

BE (X) = 240 \times 7.6 = 1824 MeV,

BE (Y) + BE (Z) = (110 + 130) \times 8.5 = 240 \times 8.5 = 2040 MeV .

Energy released

=

(BE of products)

-

(BE of parent):

Q = 2040 - 1824 = 216 MeV .

Q = 216 MeV

CBSE Class 12 Board · 2010 · Subjective