Differentiate sinx with respect to x from first principles.Answer: 2xcosxSolutionLet f(x)=sinx. By definition:f′(x)=h→0limhsinx+h−sinxApply sinC−sinD=2cos2C+Dsin2C−D:f′(x)=h→0limh2cos2x+h+xsin2x+h−xRationalise x+h−x=x+h+xh, and use θsinθ→1:f′(x)=cosx⋅h→0limhx+h−x=cosx⋅2x1dxdsinx=2xcosxCBSE Class 12 Board · 2005 · Subjective