CBSE Class 12 · 2019 · DifferentiationLong Answer

Differentiate

x^{s i n x} + (sin x)^{c o s x}

with respect to

x

Answer: $x^{s i n x} [\frac{sin x}{x} + cos x lo g x] + (sin x)^{c o s x} [cos x cot x - sin x lo g sin x]$

Solution

Let

y = u + v

with

u = x^{s i n x}, v = (sin x)^{c o s x}

.
For

u

lo g u = sin x lo g x

, so

\frac{d u}{d x} = x^{s i n x} [\frac{sin x}{x} + cos x lo g x]

.
For

v

lo g v = cos x lo g sin x

, so

\frac{d v}{d x} = (sin x)^{c o s x} [cos x cot x - sin x lo g sin x]

.
Add:

\frac{d y}{d x} = x^{s i n x} [\frac{sin x}{x} + cos x lo g x] + (sin x)^{c o s x} [cos x cot x - sin x lo g sin x]

CBSE Class 12 Board · 2019 · Subjective