Find the value of tan−13−cot−1(−3).Answer: −2πSolutiontan−13=3π. For cot−1(−3), take θ∈(0,π) with cotθ=−3: θ=π−6π=65π.tan−13−cot−1(−3)=3π−65π=62π−5π=−2π−2πCBSE Class 12 Board · 2018 · Subjective