Solve for x: tan−1(x−2x−1)+tan−1(x+2x+1)=4π.Answer: x=±21SolutionCombine using the tangent-sum formula:tan−1[1−x−2x−1⋅x+2x+1x−2x−1+x+2x+1]=4πNumerator: (x−1)(x+2)+(x+1)(x−2)=(x2+x−2)+(x2−x−2)=2x2−4.Denominator: (x−2)(x+2)−(x−1)(x+1)=(x2−4)−(x2−1)=−3.tan−1(−32x2−4)=4π ⇒ −32x2−4=12x2−4=−3 ⇒ 2x2=1 ⇒ x2=21 ⇒ x=±21x=±21CBSE Class 12 Board · 2008 · Subjective