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CBSE Class 12 · 2011 · Indefinite IntegralsVery Short Answer

Evaluate :

\int \frac{e ^{t a n^{- 1} x}}{1 + x ^{2}} d x

Answer: $e^{t a n^{- 1} x} + C$

Solution

Put

t = tan^{- 1} x

, so

d t = \frac{1}{1 + x ^{2}} d x

. Then

\int e^{t} d t = e^{t} + C .

e^{t a n^{- 1} x} + C

CBSE Class 12 Board · 2011 · Subjective

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