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CBSE Class 12 · 2011 · Indefinite IntegralsVery Short Answer

Write the value of

\int \frac{d x}{x ^{2} + 16}

Answer: $\frac{1}{4} tan^{- 1} \frac{x}{4} + C$

Solution

This is the standard form

\int \frac{d x}{x ^{2} + a ^{2}} = \frac{1}{a} tan^{- 1} \frac{x}{a} + C

with

a = 4

:

\frac{1}{4} tan^{- 1} \frac{x}{4} + C

CBSE Class 12 Board · 2011 · Subjective

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