Evaluate ∫cos2xcos2x+2sin2xdxAnswer: tanx+CSolutionUse cos2x=1−2sin2x in the numerator:cos2x+2sin2x=(1−2sin2x)+2sin2x=1.So the integrand is cos2x1=sec2x, and∫sec2xdx=tanx+CCBSE Class 12 Board · 2018 · Subjective