Find ∫(x−3)3x−5exdxAnswer: (x−3)2ex+CSolutionWrite x−5=(x−3)−2, so(x−3)3x−5=(x−3)21−(x−3)32.Take f(x)=(x−3)21; then f′(x)=−(x−3)32, so the integrand is ex{f(x)+f′(x)}. Using ∫ex{f+f′}dx=exf(x)+C:(x−3)2ex+CCBSE Class 12 Board · 2019 · Subjective