Find ∫(x−1)3x−3exdxAnswer: (x−1)2ex+CSolutionWrite x−3=(x−1)−2, so(x−1)3x−3=(x−1)21−(x−1)32.Take f(x)=(x−1)21; then f′(x)=−(x−1)32, so the integrand is ex{f(x)+f′(x)} and ∫ex{f+f′}dx=exf(x)+C:(x−1)2ex+CCBSE Class 12 Board · 2019 · Subjective