If A=12323−3−32−4, then find A−1 and hence solve the following system of equations:x+2y−3z=−4,2x+3y+2z=2,3x−3y−4z=11.Answer: x=3, y=−2, z=1 \,SolutionThe cofactors of A give adjA=−614−15175913−8−1 and ∣A∣=67, soA−1=671−614−15175913−8−1.With B=−4211, X=A−1B:xyz=671201−13467=3−21.x=3, y=−2, z=1CBSE Class 12 Board · 2024 · Subjective