Find the value of x if x+1x−3x−1x+2=41−13.Answer: x=2 \,SolutionExpand both determinants and equate.(x+1)(x+2)−(x−1)(x−3)=(4)(3)−(−1)(1).(x2+3x+2)−(x2−4x+3)=12+1 ⇒ 7x−1=13 ⇒ x=2.x=2CBSE Class 12 Board · 2013 · Subjective