Find the maximum value of 11111+sinθ1111+cosθ.Answer: 21SolutionApply C1→C1−C3 and C2→C2−C3:00−cosθ0sinθ−cosθ111+cosθ.Expanding, the value is sinθcosθ=21sin2θ. Since sin2θ≤1, the maximum is21.21CBSE Class 12 Board · 2016 · Subjective