10 mL of liquid A was mixed with 10 mL of liquid B. The volume of resulting solution was found to be 19.9 mL. What do you conclude?
Solution
On mixing, the volume contracts ( mL), so .
The new A–B interactions are stronger than the original A–A and B–B interactions — the solution is non-ideal and shows negative deviation from Raoult's law.
The new A–B interactions are stronger than the original A–A and B–B interactions — the solution is non-ideal and shows negative deviation from Raoult's law.
CBSE Class 12 Board · 2005 · All India Compartment · Subjective