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CBSE Class 12 · 2020 · SolutionsShort Answer

For a 5% solution of urea (molar mass = 60 g/mol), calculate the osmotic pressure at 300 K. (R = 0.0821 L atm K

^{- 1}

mol

^{- 1}

)

Answer: π ≈ 20.5 atm

Solution

5% solution: 5 g of urea in 100 mL of solution.
Concentration:

C = \frac{5/60}{0.100} = 0.833 mol L^{- 1}

Osmotic pressure:

π = C R T = 0.833 \times 0.0821 \times 300

π = 20.52 atm

CBSE Class 12 Board · 2020 · Subjective

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