CBSE Class 12 · 2006 · Delhi Compartment · SolutionsShort Answer

At 300 K, 36 g of glucose (C

_{6}

_{12}

_{6}

) present per litre in its aqueous solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of another solution of glucose is 1.52 bar at the same temperature, what would be its concentration?

Answer: C ≈ 0.061 mol L⁻¹

Solution

At the same temperature,

π = C R T

gives

π \propto C

.
First solution:

C_{1} = \frac{36}{180} = 0.2 mol L^{- 1}, π_{1} = 4.98 bar

Second solution:

C_{2} = C_{1} \times \frac{π _{2}}{π _{1}} = 0.2 \times \frac{1.52}{4.98}

C_{2} = 0.061 mol L^{- 1}

CBSE Class 12 Board · 2006 · Delhi Compartment · Subjective

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