CBSE Class 12 · 2003 · Delhi · Redox Reactions and ElectrochemistryVery Short Answer

Write the relation between cell potential and equilibrium constant.

Answer: E°_cell = (0.059/n) log K at 298 K (equivalently ΔG° = −nFE°_cell = −RT ln K).

Solution

At equilibrium

E_{ce l l} = 0

, and the Nernst equation gives, at 298 K:

E_{ce l l}^{\circ} = \frac{0.059}{n} lo g K

(equivalently

Δ G^{\circ} = - n F E_{ce l l}^{\circ} = - R T ln K

CBSE Class 12 Board · 2003 · Delhi · Subjective