CBSE Class 12 · 2003 · Delhi · Redox Reactions and ElectrochemistryVery Short Answer

Write the Nernst equation for a single electrode potential.

Answer: E = E° − (0.059/n) log(1/[Mⁿ⁺]) at 298 K, for Mⁿ⁺ + ne⁻ → M.

Solution

For the electrode reaction M

^{n +}

n

^{-} \to

M(s), at 298 K:

E = E^{\circ} - \frac{0.059}{n} lo g \frac{1}{[ M ^{n +} ]}

CBSE Class 12 Board · 2003 · Delhi · Subjective