Prove that the time required for the completion of three-fourths of a first order reaction is twice the time required for the completion of half of the reaction.
Answer: t₃/₄ = (2.303/k)log4 = 2×(2.303/k)log2 = 2 t₁/₂.
Solution
For a first order reaction:
Half completion ():
Three-fourths completion ():
Dividing:
Half completion ():
Three-fourths completion ():
Dividing:
CBSE Class 12 Board · 2005 · All India Compartment; also 2006 · Subjective