Let S=109+5108+52107+…+51072+51081. Then the value of (16S−(25)−54) is equal to
Answer: 2175
Solution
Let S=109+5108+52107+⋯+51081. Multiply by 51: 5S=5109+52108+⋯+51091. Subtracting: 54S=109−(51+521+⋯+51091)=109−1−1/51/5(1−1/5109)=109−41(1−51091). Thus S=45(109−41+4⋅51091). Then 16S=20⋅109−5+51081=2180−5+(25)−54. Therefore 16S−(25)−54=2175.