A solid cylinder is released from rest from the top of an inclined plane of inclination 30∘ and length 60 cm. If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is ______ ms−1. (Given g=10ms−2)
Answer: 2
Solution
Rolling without slipping, the cylinder's energy at the foot is shared between translation and rotation, giving v=1+k2/R22gh. For a solid cylinder R2k2=21, so v=3/22gh=34gh. The height dropped is h=0.60sin30∘=0.30m, hence
v=34(10)(0.30)=4=2m s−1.
JEE Main · 2023 · 01 Feb 2023 · Shift 1 · Integer answer