The value of π8∫02π(sinx)2023+(cosx)2023(cosx)2023dx is
Answer: 2
Solution
Let I=π8∫0π/2sin2023x+cos2023xcos2023xdx. Replacing x by 2π−x turns the integrand into sin2023x+cos2023xsin2023x; adding the two forms, 2I=π8∫0π/21dx=π8⋅2π=4. Therefore I=2.
JEE Main · 2023 · 24 Jan 2023 · Shift 2 · Integer answer