A wire of length 1 m moving with velocity $8 \mathrm{~m} / \mathrm{s}$ at right angles to a magnetic field of 2 T . The magnitude of induced emf, between the ends of wire will be :

JEE Main · 2023 · 25 Jan 2023 · Shift 2 · Electromagnetic Induction

A wire of length 1 m moving with velocity

8 m / s

at right angles to a magnetic field of 2 T . The magnitude of induced emf, between the ends of wire will be :

(A)20 V
(B)8 V
(C)12 V
(D)16 V✓ Correct

Answer: (D)

Solution

A straight conductor sweeping through a field at right angles develops an emf

ε = B v ℓ

. With

B = 2 T

v = 8 m/s

and

ℓ = 1 m

, the emf between its ends is

2 \times 8 \times 1 = 16 V

JEE Main · 2023 · 25 Jan 2023 · Shift 2 · Single correct option

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