A block of mass m slides down the plane inclined at angle 30∘ with an acceleration 4g. The value of coefficient of kinetic friction will be :
(A)223+1
(B)231✓ Correct
(C)23
(D)223−1
Answer: (B)
Solution
Along the incline the equation of motion is mgsin30∘−μmgcos30∘=ma with a=4g. Dividing by mg gives 21−μ23=41, so μ23=41. The coefficient of kinetic friction is 231.
JEE Main · 2023 · 29 Jan 2023 · Shift 1 · Single correct option