JEE Main · 2023 · 29 Jan 2023 · Shift 2 · Solid State

A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is

____

\times 1 0^{21}

(Nearest integer)
(Given

N_{A} = 6.02 \times 1 0^{23}

)

Answer: 36

Solution

In a close-packed structure each atom is associated with two tetrahedral voids and one octahedral void, three voids in all per atom. The number of atoms in

0.02

mol is

0.02 \times 6.02 \times 1 0^{23} = 1.204 \times 1 0^{22}

, so the total number of voids is

3 \times 1.204 \times 1 0^{22} = 3.612 \times 1 0^{22}

, which is

36 \times 1 0^{21}

to the nearest integer.

JEE Main · 2023 · 29 Jan 2023 · Shift 2 · Integer answer

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