$\mathrm{H}_{2} \mathrm{O}_{2}$ acts as a reducing agent in

(A) $2 \mathrm{NaOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$

(B) $2 \mathrm{Fe}^{2+}+2 \mathrm{H}^{+}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O}$

(C) $\mathrm{Mn}^{2+}+2 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$

(D) $\mathrm{Na}_{2} \mathrm{~S}+4 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}+4 \mathrm{H}_{2} \mathrm{O}$

JEE Main · 2023 · 31 Jan 2023 · Shift 1 · Hydrogen

H_{2} O_{2}

acts as a reducing agent in

Answer: (A)

Hydrogen peroxide acts as a reducing agent only when its peroxide oxygen, in oxidation state

- 1

, is oxidised to

O X_{2}

in oxidation state

0

. In the reaction

2 NaOCl + H X_{2} O X_{2} 2 NaCl + H X_{2} O + O X_{2}

, chlorine is reduced from

+ 1

- 1

while

H X_{2} O X_{2}

is oxidised to oxygen. In this reaction hydrogen peroxide is the reducing agent.

JEE Main · 2023 · 31 Jan 2023 · Shift 1 · Single correct option