A bullet of mass 200 g having initial kinetic energy 90 J is shot inside a long swimming pool as shown in the figure. If it's kinetic energy reduces to 40 J within 1s, the minimum length of the pool, the bullet has a to travel so that it completely comes to rest is
(A)45 m✓ Correct
(B)90 m
(C)125 m
(D)25 m
Answer: (A)
Solution
From kinetic energy, initial velocity u=2Ki/m=2×90/0.2=30 m/s. Final velocity after 1 s: v=2×40/0.2=20 m/s. Acceleration a=(v−u)/t=(20−30)/1=−10 m/s². Distance to stop: s=−u2/(2a)=−900/(−20)=45 m.
JEE Main · 2022 · 28 Jul 2022 · Shift 2 · Single correct option