JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Hydrocarbons

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A compound ' A ' on reaction with ' X ' and ' Y produces the same major product but different by product ' a ' and ' b '. Oxidation of ' a ' gives a substance produced by ants.

' X ' and ' Y ' respectively are :

(A) $KMnO_{4} / H^{+}$ and dil. $KMnO_{4}, 273 K$
(B) $KMnO_{4}$ ,(dilute), 273 K and $KMnO_{4} / H^{+}$
(C) $KMnO_{4} / H^{+}$ and $O_{3}, H_{2} O / Zn$
(D) $O_{3}, H_{2} O / Zn$ and $KMnO_{4} / H^{+}$ ✓ Correct

Answer: (D)

Solution

The compound A is an alkene. Ozonolysis (

O_{3}, H_{2} O / Zn

) produces aldehydes/ketones as by-products. Oxidative cleavage with

KMnO_{4} / H^{+}

produces carboxylic acids. Since oxidation of by-product 'a' gives formic acid (produced by ants), 'a' must be formaldehyde (from ozonolysis). Therefore, X =

O_{3}, H_{2} O / Zn

and Y =

KMnO_{4} / H^{+}

JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Single correct option

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JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Hydrocarbons

Solution

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