This is an E2 elimination reaction. The substrate reacts with alcoholic KOH (a strong base) to undergo elimination. The most stable alkene product is formed following Zaitsev's rule — the more substituted alkene is favored. Among the given options, option (B) represents the most substituted and therefore most stable alkene product. The reaction proceeds via anti-periplanar elimination of HBr to give the major product shown in (B).
JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Single correct option