A nucleus of mass M at rest splits into two parts having masses 3M′ and 32M′ (M′<M). The ratio of de Broglie wavelength of two parts will be:
(A)1:2
(B)2:1
(C)1:1✓ Correct
(D)2:3
Answer: (C)
Solution
By conservation of momentum, since the nucleus was initially at rest, the two fragments must have equal and opposite momenta: ∣P1∣=∣P2∣. The de Broglie wavelength is λ=Ph. Since both fragments have the same momentum magnitude, they have the same de Broglie wavelength. Therefore, the ratio is 1:1.
JEE Main · 2022 · 26 Jul 2022 · Shift 2 · Single correct option