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JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Biomolecules

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Match List-I with List-II

List-I
(A) Glucose + HI
(B) Glucose + water
(C) Glucose + acetic anhydride
(D) Glucose +

List-II
(I) Gluconic acid
(II) Glucose pentacetate
(III) Saccharic acid
(IV) Hexane

Choose the correct answer from the options given below:

Answer: A → IV, B → I, C → II, D → III

Solution

The correct matches are:
(A) Glucose + HI → (IV) Hexane: Complete reduction of glucose with HI/red P gives n-hexane
(B) Glucose + Br₂ water → (I) Gluconic acid: Mild oxidation of aldehyde group to carboxylic acid
(C) Glucose + acetic anhydride → (II) Glucose pentacetate: Acetylation of all five -OH groups
(D) Glucose + HNO₃ → (III) Saccharic acid: Strong oxidation converts both terminal groups (CHO and CH₂OH) to COOH
Structure A
A
Structure B
B
Structure C
C
Structure D
D

JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Match the columns

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