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JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Practical and Analytical Chemistry

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Match List-I with List-II

List-I (Mixture)
(A) Chloroform & Aniline
(B) Benzoic acid & Napthalene
(C) Water & Aniline
(D) Napthalene & Sodium chloride

List-II (Purification Process)
(I) Steam distillation
(II) Sublimation
(III) Distillation
(IV) Crystallisation

Answer: A → III, B → IV, C → I, D → II

Solution

The correct separation methods are:
(A) Chloroform & Aniline → (III) Distillation: Both are volatile liquids with different boiling points, so simple distillation can separate them
(B) Benzoic acid & Naphthalene → (IV) Crystallisation: Benzoic acid is more soluble in hot water than naphthalene, allowing separation by crystallization
(C) Water & Aniline → (I) Steam distillation: Aniline is immiscible with water and volatile with steam, making steam distillation ideal
(D) Naphthalene & Sodium chloride → (II) Sublimation: Naphthalene sublimes on heating while NaCl does not

JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Match the columns

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