Reaction of BeCl₂ with LiAlH₄ gives:
(A) AlCl₃
(B) BeH₂
(C) LiH
(D) LiCl
(E) BeAlH₄
Choose the correct answer from options given below:
(A) AlCl₃
(B) BeH₂
(C) LiH
(D) LiCl
(E) BeAlH₄
Choose the correct answer from options given below:
- (A)(A), (D) and (E)
- (B)(A), (B) and (D)✓ Correct
- (C)(D) and (E)
- (D)(B), (C) and (D)
Answer: (B)
Solution
The reaction between BeCl₂ and LiAlH₄ is a metathesis reaction:
The products formed are:
Answer: (B) (A), (B) and (D).
The products formed are:
- BeH₂ (beryllium hydride)
- LiCl (lithium chloride)
- AlCl₃ (aluminum chloride)
Answer: (B) (A), (B) and (D).
JEE Main · 2022 · 26 Jul 2022 · Shift 1 · Single correct option