The probability that a randomly chosen one-one function from the set {a,b,c,d} to the set {1,2,3,4,5} satisfies f(a)+2f(b)−f(c)=f(d) is :
(A)241
(B)401
(C)301
(D)201✓ Correct
Answer: (D)
Solution
Total one-one functions from a 4-element set to a 5-element set: n(S)=5C4×4!=120. For the condition f(a)+2f(b)=f(c)+f(d), we find valid assignments: (5,1,3,4), (4,2,3,5), (1,3,2,5). Each can be permuted among the four variables in 2 ways (since the equation is symmetric in certain pairs), giving n(A)=3×2=6 favorable outcomes. Therefore, P(A)=1206=201.
JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Single correct option