Two coils of self inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self inductance of the combination will be :
(A)L11+L21+M1
(B)L1+L2+M
(C)L1+L2+2M
(D)L1+L2−2M✓ Correct
Answer: (D)
Solution
When two inductors are connected in series with mutual inductance M, the equivalent inductance depends on the relative direction of the currents. From the circuit diagram provided, the currents in both inductors flow in opposite directions through the mutual inductance region. Therefore, the mutual inductance subtracts: Leq=L1+L2−2M.
JEE Main · 2022 · 26 Jun 2022 · Shift 2 · Single correct option