16sin(20∘)sin(40∘)sin(80∘) is equal to :(A)3(B)23✓ Correct(C)3(D)43Answer: (B)SolutionUsing the identity sin3θ=4sin(60∘−θ)sinθsin(60∘+θ):16sin20∘sin40∘sin80∘=4×4sin20∘sin(60∘−20∘)sin(60∘+20∘)=4×sin(3×20∘)=4sin60∘=4×23=23.Answer: (B)JEE Main · 2022 · 26 Jun 2022 · Shift 2 · Single correct option