A 110V,50Hz,AC source is connected in the circuit (as shown in figure). The current through the resistance 55Ω, at resonance in the circuit, will be ____ A.
Answer: 0
Solution
At resonance in a parallel LC circuit, the inductive and capacitive currents are equal and opposite: IL=IC. These currents cancel each other out in the main branch.
Since the inductor and capacitor are in parallel and at resonance XL=XC, the impedance of the parallel LC combination becomes infinite: Z→∞.
Therefore, the total circuit impedance is infinite, and the current through the resistor (and the entire circuit) is 0 A.
JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Integer answer