As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is πaA. The value of a is ______.
Answer: 242
Solution
Inductive reactance: XL=2πfL=2π×50×200×10−3=20πΩ
Peak current: i0=XLV0=XLVrms2=20π2202
i0=π112=π121×2=π242
Comparing with πa, we get a=242.
JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Integer answer