The energy of one mole of photons of radiation of wavelength 300 nm is (Given : $\mathrm{h}=6.63 \times 10^{-34}$ Js, $\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23}$ mol$^{-1}$, c $=3 \times 10^{8}$ ms$^{-1}$ )

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Atomic Structure

The energy of one mole of photons of radiation of wavelength 300 nm is
(Given :

h = 6.63 \times 1 0^{- 34}

Js,

N_{A} = 6.02 \times 1 0^{23}

mol

^{- 1}

, c

= 3 \times 1 0^{8}

^{- 1}

)

Answer: (C)

The energy of one mole of photons is given by

E = \frac{h c}{λ} \times N_{A}

.

Substituting the values:

E = \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{300 \times 1 0 ^{- 9}} \times 6.02 \times 1 0^{23}

E = 399.13 \times 1 0^{3}

J/mol

= 399

kJ/mol

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Single correct option