$\mathrm{PCl}_{5}$ is well known, but $\mathrm{NCl}_{5}$ is not. Because.

(B) nitrogen doesn't have d-orbitals in its valence shell.

(A) nitrogen is less reactive than phosphorous.

(C) catenation tendency is weaker in nitrogen than phosphorous.

(D) size of phosphorous is larger than nitrogen.

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · p-Block Elements

PCl_{5}

is well known, but

NCl_{5}

is not. Because.

(A)nitrogen is less reactive than phosphorous.
(B)nitrogen doesn't have d-orbitals in its valence shell.✓ Correct
(C)catenation tendency is weaker in nitrogen than phosphorous.
(D)size of phosphorous is larger than nitrogen.

Answer: (B)

Solution

Phosphorus can form

PCl_{5}

by utilizing its vacant 3d orbitals to expand its octet and accommodate five bonds. Nitrogen, being in the second period, has no d-orbitals available in its valence shell (n=2). Therefore, nitrogen cannot expand its octet beyond four bonds, and

NCl_{5}

does not exist.

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Single correct option

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