JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Practical and Analytical Chemistry

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0.2 g

of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of

N X_{2}

evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is ____. [nearest integer]
(Given: Molar mass of

N X_{2}

28 g mol^{- 1}

. Molar volume of

N X_{2}

at STP: 22.4 L)

Answer: 14

Solution

In Dumas method, nitrogen is converted to

N X_{2}

gas.

Volume of

N X_{2}

at STP = 22.400 mL = 0.0224 L

Moles of

N X_{2}

\frac{0.0224}{22.4} = 0.001

mol

Mass of

N X_{2}

0.001 \times 28 = 0.028

g

Mass of nitrogen atoms = 0.028 g (since all nitrogen in

N X_{2}

came from the compound)

Percentage of nitrogen =

\frac{0.028}{0.2} \times 100 = 14%

Answer: 14

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Integer answer

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