JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Biomolecules

A protein 'A' contains

0.30%

of glycine (molecular weight 75). The minimum molar mass of the protein 'A' is

____

\times 1 0^{3} g mol^{- 1}

[nearest integer]

Answer: 25

Solution

If the protein contains

0.30%

glycine by mass, then in 100 g of protein there are 0.30 g of glycine. For the minimum molar mass, we assume exactly one glycine residue per protein molecule. Using the formula:

Minimum molar mass = \frac{Molecular weight of glycine \times 100}{Percentage} = \frac{75 \times 100}{0.30} = 25000 g mol^{- 1}

Expressing in the required form:

25000 = 25 \times 1 0^{3}

g mol

^{- 1}

Answer: 25

JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Integer answer

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