JEE Main · 2022 · 25 Jun 2022 · Shift 1 · d and f Block Elements

The strength of an oxidizing agent is determined by its reduction potential — higher reduction potential means stronger oxidizing agent.

The standard reduction potentials are:

• $E_{{\mathrm{Mn}}^{3+}/{\mathrm{Mn}}^{2+}}^0=+1.51\mathrm{V}$ (highest)
• $E_{{\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}}^0=+0.77\mathrm{V}$
• $E_{{\mathrm{Ti}}^{3+}/{\mathrm{Ti}}^{2+}}^0\approx -0.37\mathrm{V}$
• $E_{{\mathrm{Cr}}^{3+}/{\mathrm{Cr}}^{2+}}^0\approx -0.41\mathrm{V}$

Since ${\mathrm{Mn}}^{3+}$ has the highest reduction potential (+1.51 V), it is the strongest oxidizing agent among the given options.

The answer is ${\mathrm{Mn}}^{3+}$.