The reaction involves a bulky base (potassium tert-butoxide), which favors elimination (E2) over substitution. With a bulky base, the less substituted alkene (Hofmann product) is formed preferentially. The substrate undergoes β-elimination to give 2-methylprop-1-ene as the major product. The correct answer is (D).
JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Single correct option