JEE Main · 2021 · 24 Feb 2021 · Shift 2 · p-Block Elements

Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is

____

(A)

α

- sulphur
(B)

β

- sulphur
(C)

S_{2}

- form

Answer: 1

Solution

Paramagnetism requires unpaired electrons. Both

α

-sulphur and

β

-sulphur are built from puckered

S_{8}

rings in which every valence electron belongs either to a bond pair or to a lone pair, so both of these allotropes are diamagnetic. The

S_{2}

molecule has the same molecular orbital arrangement as

O_{2}

, with its last two electrons singly occupying the two degenerate

π^{*}

orbitals, so it carries two unpaired electrons and is paramagnetic. The number of paramagnetic forms among the three listed is

1

JEE Main · 2021 · 24 Feb 2021 · Shift 2 · Integer answer

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