JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Practical and Analytical Chemistry

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When 0.15 g of an organic compound was analyzed using carius method for estimation of bromine, 0.2397 g of AgBr was obtained. The percentage of bromine in the organic compound is ______. (Nearest Integer)
(Atomic mass:

Ag = 108, Br = 80

)

Answer: 68

Solution

Each mole of silver bromide carries one mole of bromine, and the molar mass of silver bromide is

108 + 80 = 188

g mol

^{- 1}

. The bromine held in the precipitate is

m_{Br} = \frac{80}{188} \times 0.2397 = 0.1020 g

and this came from the 0.15 g of compound taken, so

% Br = \frac{0.1020}{0.15} \times 100 = 68

The percentage of bromine in the organic compound is 68.

JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Integer answer

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