Match List - I with List - II : List - I (a) h (Planck's constant) (b) E (kinetic energy) (c) V (electric potential) (d) P (liner momentum ) List - II (i) $\left[\mathrm{M} \mathrm{L} \mathrm{T}^{-1}\right]$ (ii) $\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-1}\right]$ (iii) $\left[\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-2}\right]$ (iv) $\left[\mathrm{M} \mathrm{L}^{2} \mathrm{I}^{-1} \mathrm{~T}^{-3}\right]$ Choose the correct answer from the options given below :

The dimensional formulas are: - Planck's constant → (ii) - Kinetic energy → (iii) - Electric potential → (iv) - Linear momentum → (i) Therefore: (a)→(ii), (b)→(iii), (c)→(iv), (d)→(i), which corresponds to option (C).

JEE Main · 2021 · 25 Feb 2021 · Shift 1 · Units & Measurement

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Match List - I with List - II :

List - I
(a) h (Planck's constant)
(b) E (kinetic energy)
(c) V (electric potential)
(d) P (liner momentum )

List - II
(i)

[ML T^{- 1}]

(ii)

[M L^{2} T^{- 1}]

(iii)

[M L^{2} T^{- 2}]

(iv)

[M L^{2} I^{- 1} T^{- 3}]

Choose the correct answer from the options given below :

Answer: A → II, B → III, C → IV, D → I

Solution

The dimensional formulas are:

Planck's constant $h = E / ν = [M L^{2} T^{- 2}] / [T^{- 1}] = [M L^{2} T^{- 1}]$ → (ii)
Kinetic energy $E = \frac{1}{2} m v^{2} = [M L^{2} T^{- 2}]$ → (iii)
Electric potential $V = W / q = [M L^{2} T^{- 2}] / [I T] = [M L^{2} I^{- 1} T^{- 3}]$ → (iv)
Linear momentum $P = m v = [M L T^{- 1}]$ → (i)

Therefore: (a)→(ii), (b)→(iii), (c)→(iv), (d)→(i), which corresponds to option (C).

JEE Main · 2021 · 25 Feb 2021 · Shift 1 · Match the columns

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JEE Main · 2021 · 25 Feb 2021 · Shift 1 · Units & Measurement

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